在Linux计算机上,从cmake项目中,我试图使用execute_process调用git,以便可以将源代码控制中的信息包含到我的应用程序中。
我创建了一个小测试来尝试打印git版本:
cmake_minimum_required (VERSION 2.8)
set (git_cmd "/usr/bin/git --version")
#set (git_cmd "ls") # returns success if you uncomment this line
message(STATUS "git cmd: ${git_cmd}")
execute_process(COMMAND ${git_cmd}
WORKING_DIRECTORY ${PROJECT_SOURCE_DIR}
RESULT_VARIABLE git_result
OUTPUT_VARIABLE git_ver)
message(STATUS "git ver[${git_result}]: ${git_ver}")
configure_file (
"${PROJECT_SOURCE_DIR}/versionInfo.h.in"
"${PROJECT_BINARY_DIR}/versionInfo.h"
)
运行make时,将提供以下输出:
-- git cmd: /usr/bin/git --version
-- git ver[No such file or directory]:
-- Configuring done
-- Generating done
-- Build files have been written to: /home/rsanderson/build/githash:
但是,如果将命令更改为
ls
,则结果有效,并且我看到目录列表已打印。我还检查了/ usr / bin中确实存在哪些git。
关于我在这里缺少什么的任何想法?
请您参考如下方法:
您必须像这样将参数作为第二个选项传递:
cmake_minimum_required (VERSION 2.8)
set (git_cmd "git")
set (git_arg "--version")
message(STATUS "git cmd: ${git_cmd}")
execute_process(COMMAND ${git_cmd} ${git_arg}
WORKING_DIRECTORY ${PROJECT_SOURCE_DIR}
RESULT_VARIABLE git_result
OUTPUT_VARIABLE git_ver)
message(STATUS "git ver[${git_result}]: ${git_ver}")