//单链表的使用:快慢指针,如何找中间值 public static void main(String[] args) { Node<Integer> node1 = new Node(1,null); Node<Integer> node2 = new Node(2,null); Node<Integer> node3 = new Node(3,null); Node<Integer> node4 = new Node(4,null); Node<Integer> node5 = new Node(5,null); Node<Integer> node6 = new Node(5,null); node1.next = node2; node2.next = node3; node3.next = node4; node4.next = node5; node5.next = node6; Node quick = node1; Node low = node1; while (quick != null && quick.next != null){ quick = quick.next.next; low = low.next; } System.out.println("中间值:" + low.t); } private static class Node<T>{ private T t; private Node next; public Node(T t, Node next) { this.t = t; this.next = next; } }
本文参考链接:https://www.cnblogs.com/maohuidong/p/14216285.html