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flask之如何对 JSONB 内容运行 Flask-reSTLess api 过滤器查询

2025年12月25日21kerrycode

我在尝试对 JSONB 对象中包含的数据执行无 flask api 查询时遇到了麻烦。我猜这是因为底层查询不知道如何转换数据字段,所以它不知道如何正确生成查询,但我不确定。

当我执行 ajax 搜索时运行的查询:

http://192.168.163.129:1080/api/subscribers?page=1&results_per_page=10&q={"filters":[{"name":"data","op":"has","val":{"name":"full_name","op":"eq","val":"%Steve%"}}],"order_by":[{"field":"created","direction":"asc"}]} 

这是我运行查询时得到的回溯。
2016-12-29 22:26:33,068 - app - ERROR - mapper 
Traceback (most recent call last): 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/views.py", line 1172, in _search 
    result = search(self.session, self.model, search_params) 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 587, in search 
    query = create_query(session, model, search_params, _ignore_order_by) 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 549, in create_query 
    _ignore_order_by) 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 480, in create_query 
    filters = [create_filt(model, filt) for filt in search_params.filters] 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 438, in _create_filter 
    return create_op(model, fname, filt.operator, val, relation) 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 411, in _create_operation 
    return opfunc(field, argument, fieldname) 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 106, in <lambda> 
    'has': lambda f, a, fn: f.has(_sub_operator(f, a, fn)), 
  File "/usr/local/lib/python2.7/dist-packages/flask_restless/search.py", line 37, in _sub_operator 
    submodel = model.property.mapper.class_ 
  File "/usr/local/lib/python2.7/dist-packages/sqlalchemy/util/langhelpers.py", line 833, in __getattr__ 
    return self._fallback_getattr(key) 
  File "/usr/local/lib/python2.7/dist-packages/sqlalchemy/util/langhelpers.py", line 811, in _fallback_getattr 
    raise AttributeError(key) 
AttributeError: mapper 

API 代码:
manager.create_api(Subscribers, methods=['GET'], results_per_page=10, 
                   preprocessors=dict(GET_SINGLE=[subscribers_preprocessor], 
                                      GET_MANY=[subscribers_preprocessor])) 

预处理器是一个简单的认证处理器。

知道如何正确格式化过滤器以过滤 JSONB postgres 字段吗?

请您参考如下方法:

在这一点上的答案是,你不能像以前那样使用 flask-reSTLess。

我对 flask-reSTLess 进行了一些修改,以拆分特殊格式的查询字符串并将查询正确转换为 jsonb。有点痛苦,而且可能无法扩展。

它被标记为在flask-reSTLess git上进行增强。

https://github.com/jfinkels/flask-restless/issues/623